使用面向对象思想，实现（人狗大战）小游戏c727657851的博客-

 学习面向对象之后，练习使用面向对象思想，实现代码

 # -*- coding: utf-8 -*-  # @File : 面向对象小游戏.py  # 描述 : 人狗大战 # @Time : 2020/6/3 16:27  # @Author : 崔 # @versions : 1.0 from random import randint   class Person:     def __init__(self, name, aggressivity, hp):   # 姓名 攻击力 生命值         self.name = name         self.aggressivity = aggressivity         self.hp = hp      def attack(self, dog):         atk = randint(0, self.aggressivity)         if dog.hp > atk:             dog.hp -= atk             print(f"{self.name}打了{dog.name}一下")         else:             dog.hp -= atk             print(f"{dog.name}死翘翘了")   class Dog:     def __init__(self, name, aggressivity, hp):         self.name = name         self.aggressivity = aggressivity         self.hp = hp      def attack(self, person):         atk = randint(0, self.aggressivity)  # 随机的攻击力         if person.hp > atk:             person.hp -= atk             print(f"{self.name}咬了{person.name}一下")         else:             person.hp -= atk             print(f"{person.name}被咬死了")   person = [Person("张三", 9, 100), Person("李四", 9, 100), Person("王二", 9, 100)] dogs = [Dog("豆豆", 20, 60), Dog("贝贝", 20, 90)]  while len(person) > 0 and len(dogs) > 0:     person[randint(0, len(person) - 1)].attack(dogs[randint(0, len(dogs) - 1)])     for i in range(len(dogs) - 1, -1, -1):         if dogs[i].hp <= 0:             dogs.pop(i)  # 将已死的狗从列表中删除     if len(dogs) <= 0:         break     dogs[randint(0, len(dogs) - 1)].attack(person[randint(0, len(person) - 1)])     for i in range(len(person) - 1, -1, -1):         if person[i].hp <= 0:             person.pop(i)   # 将已死的人从列表中删除  if len(person) > 0:     print("人获得了胜利") else:     print("狗获得了胜利") 

使用了随机攻击的方式，因此运行结果不一定相同